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  1 . 3[tex] \frac{1}{3} [/tex] :1[tex] \frac{1}{9} [/tex]
2. [tex] \frac{65}{8} [/tex] : 4 [tex] \frac{1}{16} [/tex]

Răspuns :

3intreg1/3=(3x3+1)/3=10/3
1intreg1/9=(1x9+1)/9=10/9
10/3:10/9=10/3x9/10=simplif.cu 10=9/3=3
2)
4intreg1/16=(4x16+1)/16=64/16
65/8:64/16=65/8x16/64=simplif.cu 8=65/1x2/64=130/64=simplif.cu 2=
=65/32

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