Modul x+2 = 0,8(3)
x+2=0,8(3) SAU x+2= -0,8(3)
x+2=[tex] \frac{5}{6} [/tex]
[tex] \frac{6x+12}{6} [/tex] = [tex] \frac{5}{6} [/tex]
6x+12=5
x= -[tex] \frac{7}{6} [/tex]
SAU
x+2 = -[tex] \frac{5}{6} [/tex]
[tex] \frac{6x+2}{12} [/tex] = - [tex] \frac{5}{6} [/tex]
6x+12= -5
6x= - 17
x= -[tex] \frac{17}{6} [/tex]
x ∈ -[tex] \frac{17}{6} [/tex] ȘI [tex] \frac{7}{6} [/tex]
