|2x+5|+(x+1)=3
pt x<-5/2
-2x-5+x+1=3
-x-4=3
-4-3=x
x=-7<-5/2 deci solutyie buna
pt x≥-5/2
2x+5+x+1=3
3x=3-6
3x=-3
x=-1∈[-5/2;∞) deci buna
S={-7;-1}
ambele vrifica, daca inlocuiesti
|2x-5|=|3x-5|
avem 4 ecuatiicarese reduc la 2
2x-5=3x-5
0=x
x=0
si
2x-5=-3x+5
5x=10 x=2
S={0;2}
ambele verifica
