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a fost răspuns

(8 la puterea 4 ÷4 la puterea 5 + 27 la puterea 9÷3 la puterea 24 +2 la puterea 12 ÷2 la puterea 11)÷3

Răspuns :

Dely124
(2^3)^4:(2^2)^5+(3^3)^9:3^24+2^12-11):3= (2^12:2^10+3^27:3^24+2^1):3= (2^12-10+3^27-24+2):3= (2^2+3^3+2):3= (4+27+2):3= 33:3=11

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