a)1/2 3+1/3 4+...+1/31 32-15/32=1/2-1/3+1/3-1/4+...+1/31-1/32-15/32=1/2-1/32-15/32=15/32-15/32=0
b)1/10 11+1/11 12+...+1/49 50-2,39+1.59=1/10-1/11+1/11-1/12+...+1/49-1/50-0.8=(dupa reducerea termenilor)=1/10-1/50-8/10=-18/25
In mod analog se rezolva celelalte subpuncte
