Răspuns :
x+4y+2z=13
3x+2z=11
x+y+z=?
(x+4y+2z)+(3y+2z)=13+11
4x+4y+4z=24
4*(x+y+z)=24
x+y+z=24:4
x+y+z=6
3x+2z=11
x+y+z=?
(x+4y+2z)+(3y+2z)=13+11
4x+4y+4z=24
4*(x+y+z)=24
x+y+z=24:4
x+y+z=6