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a fost răspuns

E(x )=[2x]-[x]-[x+1/2]
x∈[0,1/2)
E(X)=0

Răspuns :

JolieJulie
Salut

E(x)=[2x]-[x]-[x+1/2]
x∈[0,0.5)
E(X)=0
________
E(x)=[2x]-[x]-[x+0.5]
E(x)=2[x]-[x]-[x+0.5]
daca 0≤ x<0,5 => [x+0.5] <1
=> [x+0,5]=[x]
=> E(x)=2[x]-[x]-[x]
=> E(x)=0 - q.e.d


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