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folosind operatiile cu numere complexe scrie sub forma trigonometrica : (2+2i) (1-i√3)

Răspuns :

C04f
{2+2i)(1-i√3)=2√2(√2/2+i√2/2)·2(1/2-i√3/2)=4√2[cos(π/4)+isin(π/4)]
[cos(5π/3)+sin(5π/3)]=4√2[cos(π/4+5π/3)+isin(π/4+5π/3)]=
=4√2[cos(23π/12)+isin(23π/12)]

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