Răspuns :
c = Q / m x variatie de temperatura (Δt)
Δt = tf - ti = 60° -20° = 40°
4187 = Q / 2 x 40
Q = 4187 x 40 x 2
Q = 4187 x80
Q = 334960 Joule
Δt = tf - ti = 60° -20° = 40°
4187 = Q / 2 x 40
Q = 4187 x 40 x 2
Q = 4187 x80
Q = 334960 Joule
m=2kg
delta T = 60 grade -20 grade =40 grade
c=4187 j\kg.K
si de aici faci tu aplicand formula caldurii Q=m.c.delta T
delta T = 60 grade -20 grade =40 grade
c=4187 j\kg.K
si de aici faci tu aplicand formula caldurii Q=m.c.delta T