👤
Georgi
a fost răspuns

transforma inmultirile in adunari repetate si rezolva: 3×4 5×5 6×5 4×2 3×4 6×3 2×9 3×7

Răspuns :

MaestraCifrelor
3×4=3+3+3+3=4+4+4=12
5×5=5+5+5+5+5=25
6×5=6+6+6+6+6=5+5+5+5+5+5=30
4×2=4+4=2+2+2+2=8
6×3=6+6+6=3+3+3+3+3+3=18
2×9=2+2+2+2+2+2+2+2+2=9+9=18
3×7=7+7+7=3+3+3+3+3+3+3=21.