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Alinaclau2000
a fost răspuns

daca 408:[2×3la puterea2+2la puterea20:8la puterea6+1+27la puterea13:3la puterea 39]este prim?

Răspuns :

Didi12342
408 : [2×3^2 + 2^20:8^6+1+27^13:3^39] =

= 408:(2×9+2^20:2^18+1+3^39:3^39) =

= 408:(18+2^2 + 1 + 1) =

= 408 : (18 + 4 + 2) =

= 408 : 24 =

= 17 (este numar prim)

17 = 1 × 17

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