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Afla suma numerelor a si b stiind ca:a+116:2=(1991:11-4):3si b:11-4=(4+110)×3

Răspuns :

Iamale47
a+116:2=(1991:11-4):3
a+58=(181-4):3
a+58=177:3
a+58=59
a=59-58
a=1

b:11-4=(4+110)×3
b:11-4=114×3
b:11-4=342
b:11=342+4
b:11=346
b=346×11
b=3806

a+b=1+3806=3807

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