AA' || BB' = 0 grade
DC =CD => m ( DC ; CD ) = 0 grade
m ( AB ; BC ) = m ( ABC ) = 90 grade
DC || AB => m(DC ;A'B ) = m ( AB ; A'B ) = m ( A'BA ) = 45 grade
AB || A'B' => m ( AB ; A'D' ) = m ( A'B' ; A'D' ) = m (B'A'D' ) = 90 grade
BC' ; B'C - diagonale = 90 grade
m ( A'B ; AB ) = m ( A'BA ) = 45 grade
BC ' ; AC = 0 grade
BC || B'C' => m ( A'C' ; BC ) = m ( A'C' ; B'C' ) = m ( A'C'B' ) = 45 grade
Sper ca te-am ajutat !
