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Marinavalentina
a fost răspuns

calculeaza grupand termeni avantajosi:1+2+3+4+5 = ?? 3+25+2= ?? 1+36+9= ??? 10+20+30+40=?? 11+33+22= ??? 1+2+3+9+8+7= ??? pt clasa a II a dupa culegere


Răspuns :

CosmoteRo
1+2+3+4+5=(1+4+5)+(2+3)=10+5=15
3+25+2=(3+2)+25=5+25=30
1+36+9=(1+9)+36=10+36=46
10+20+30+40=(10+40)+(20+30)=50+50=100
11+33+22=(11+22)+33=33+33=66
1+2+3+9+8+7=(1+9)+(2+8)+(3+7)=10+10+10=30

Alte intrebari