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Afla suma nr a si b stiind ca : a +116:2=(1991:11-4):3 si b:11-4=(4+110:2)x3

Răspuns :

Didi12342
a +116:2=(1991:11-4):3
a + 58 = (181 -4) : 3
a + 58 = 177 : 3
a + 58 = 59
a = 59 - 58
a = 1

b:11-4=(4+110:2)x3
b: 11- 4 = (4+55)×3
b :11 -4 = 59 × 3
b:11 - 4 = 177
b:11 = 177 + 4
b:11 = 181
b = 1 991

a+b = 1 + 1991 = 1 992

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