HCl+ Al = AlCl3 + H2
Se egaleaza:
6HCl+ 2Al = 2AlCl3 + 3H2
Stiind formula: c=(Md/Ms)*100
73=(Md/200)*100
=>73=Md/2
=>Md=146g HCl pur
MHCl= 1+35.5
MHCl=36.5g/mol
Prin regula de 3 simpla:
1mol.....36.5g
xmoli....146g
=> x= 4 moli HCl
MAl=27g/mol
Notam deasupra lui HCl(in ecuatia egalata) 6*36.5
Sub HCl notam 146g
Deasupra lui Al notam 2*27
Sub Al notam x
Din proportie:
(6*36.5)/146=(2*27)/x
=>x=36g Al
