Răspuns :
compusul are formula moleculara CH(4-x)Brx si are masa molara
M= 12g+(4-x)gH+x 80 gBr
in (16+ 79x) g compus....sunt 80x, g brom
100g..........................................94,86g
8000x= 94,86(16+79x)=========> x=3----> CHBr3
M= 12g+(4-x)gH+x 80 gBr
in (16+ 79x) g compus....sunt 80x, g brom
100g..........................................94,86g
8000x= 94,86(16+79x)=========> x=3----> CHBr3
CH(4-x)Brx
80x·100/(16-x+80x) = 94,86
84,33x = 16 +79x 5,33x = 16 x = 3 CHBr3
80x·100/(16-x+80x) = 94,86
84,33x = 16 +79x 5,33x = 16 x = 3 CHBr3