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a fost răspuns

a) (2x+5)[3(x-2)-2(x-4)]+2(2x+5)=
b) 3x(x-2)+[tex] (x-2)^{2} [/tex]-5(x-2)=
c) (x-1)(x-2)+4[tex] (x-1)^{2} [/tex]-4x(x-1)=
d) (x-4)(3x+7)-(x-4)(4x+2)+3(x-4)=
e) [tex] (2x+1)^{2} [/tex]-(3x-2)(3x+1)+3x(2x+1)=
f) (4x-5)[tex] (3x+2)^{2} [/tex]-[tex] (3x+2)^{3} [/tex]+2(x+4)[tex] (3x+2)^{2} [/tex]=
g) (5x-3)(3x+4)-[tex] 2(3x+4)^{2} [/tex]+3x(3x+4)=

Răspuns :

Economist
a) ( 2x + 5)( 3x - 6 - 2x + 8) + 2( 2x + 5) =
     = ( 2x + 5)( x + 2) + 2( 2x + 5) =
     = ( 2x + 5)( x + 2 + 2) =
     = ( 2x + 5)( x + 4)
b)  ( x - 2)[ 3x + ( x - 2) - 5] =
     = ( x - 2)( 3x + x - 2 - 5) =
     = ( x - 2)( 4x - 7)
c)  ( x - 1)[ x - 2  + 4(x - 1) - 4x] =
     = ( x - 1)( x - 2 + 4x - 4 - 4x) =
     = ( x - 1)( x - 2)
d)  ( x - 4)[ 3x + 7 - ( 4x + 2)+ 3] =
   = ( x - 4)( 3x + 7 - 4x - 2 + 3) =
   = ( x - 4)( - x + 8)
  = ( x - 4)( 8 - x)
e)  ( 2x + 1)[ 2x + 1 - ( 3x - 2) + 3x] =
     = ( 2x + 1)( 2x + 1 - 3x + 2 + 3x) =
     = ( 2x + 1)( 2x + 3)
f)  ( 3x + 2)²[ ( 4x - 5) - (3x - 2) + 2( x + 4)] =
   = ( 3x + 2)²( 4x - 5 - 3x + 2 + 2x + 8) =
   = ( 3x + 2)²( 3x + 5)
g)  ( 3x + 4)[ 5x - 3 - 2( 3x + 4) + 3x] =
   = ( 3x + 4)( 5x - 3 - 6x - 8 + 3x) =
   = ( 3x + 4)( 2x - 11)

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