1.nesaturate
2. formula moleculara
3.trei legaturi sigma si una pi
4.M(masa molara) CH3OH=12x1 + 4x1+16x1 =32g/mol
daca in 32 g.......................................... intra 12 g Carbon
in 100 .............................................x
iar de acolo rezulta x=100x12 supra 32
= 37.5 % C
5.formula bruta