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Luisa057
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Determina numerele naturale m,n,p,r si s, aseaza-le in ordine descrescatoare, stiind ca acestea indeplinesc simultan conditiile:
m+n=2, m+p=14, m+r=16, m+s=18 si n+p+r+s=42.
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Răspuns :

Renatemambouko
m+n=2, m+p=14, m+r=16, m+s=18 si n+p+r+s=42

m+n+ m+p+ m+r+ m+s=2+14+16+18=50
4m+n+p+r+s=50
4m+42=50
m=(50-42)/4=2
n=2-2=0
p=14-2=12
r=16-2=14
s=18-2=16
n=0
m=2
p=12
r=14
s=16
m+n = 2,
m+p =14,
m +r =16,
 m+s =18
4m+42=50 deci 4m=50-42  
adica m=2 ;
2+n=2 deci n=0
2+p=14 deci p=12
2+r=16 deci r=14
2+s=18 deci s=16

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