[tex]x \geq \frac{4-2 \sqrt{8} }{1- \sqrt{2} } [/tex]
[tex]\frac{4-2 \sqrt{8} }{1- \sqrt{2} } =\frac{(4-2 \sqrt{8})(1+ \sqrt{2}) }{(1- \sqrt{2})(1+ \sqrt{2}) }= \frac{4+4 \sqrt{2}-4 \sqrt{2}-8 }{1+ \sqrt{2}- \sqrt{2}-2 }= \frac{-4}{-1}=4 [/tex]
x≤4
x={0,1,2,3,4}
