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Lorentz123456
a fost răspuns

am nevoe acuma de rezolvare,dau 70 punkte..va rog e foarte urgent am evaluare acuma!!!
trebu de aflat puteria degajata in circuit P=?
va roooooooog mult !!!

Am Nevoe Acuma De Rezolvaredau 70 Punkteva Rog E Foarte Urgent Am Evaluare Acumatrebu De Aflat Puteria Degajata In Circuit Pva Roooooooog Mult class=

Răspuns :

P=I²R

1/R=1/R13+1/R24

R13=R1+R3
R24=R2+R4

1/R=1/(R1+R3)+1/(R2+R4)
1/R=(R1+R2+R3+R4)/(R1+R3)(R2+R4)
R=(R1+R3)(R2+R4)/(R1+R2+R3+R4)

P=I²(R1+R3)(R2+R4)/(R1+R2+R3+R4)

P=0,15²(50+150)(150+50)/(50+150+50+150)=2,25W

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