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calculati masa de solutie de acid sulfuric 19,6% care reactioneaza cu 140 g cu 20% impuritati. URGENT!!!!!

Răspuns :

a) C=md/ms*100=>md=50*20/100=10g NaOH

2NaOH + H2SO4 => Na2SO4 + 2H2O

2*40g NaOH...............98g H2SO4
10g NaOH..................x=12,25g H2SO4

C=md/ms*100=>ms=md*100/C=1225/19,6= Calculeaza !

b) C=md/ms*100 => md=18,25*300/100=54,75g HCl

n=m/M=54,75/36,5=1,5 moli HCl

2Al + 6HCl -> 2AlCl3 + 3H2

2 moli Al................6 moli HCl
x moli Al................1,5 moli HCl

x=1,5*2/6= Calculeaza !!

c) C=md/ms*100=>md=22,2*4/100=0,888kg=888g CaCl2

CaCl2 + Na2CO3 => CaCO3 + 2NaCl

111g CaCl2...................100g CaCO3
888g CaCl2......................xg CaCo3

x=88800/111=800g CaCO3=0,8kg CaCO3