Răspuns :
not. cu x,y,z zilele
x+y+z=1270
x=prima ziy=a doua ziz=a treia zi
x=5*yz=60+xz=60+5*y
5*y+y+60+5*y=127011y+60=127011y=1270-6011y=1210
y=110
x=5*yx=5*110x=550
z=60+xz=60+550z=610
x+y+z=1270
x=prima ziy=a doua ziz=a treia zi
x=5*yz=60+xz=60+5*y
5*y+y+60+5*y=127011y+60=127011y=1270-6011y=1210
y=110
x=5*yx=5*110x=550
z=60+xz=60+550z=610
1 -----
2 -
3 -----+60km
din total 1270-60=1210
1210:11=110
1zi 110×5
2zi 110
3zi 550+60
2 -
3 -----+60km
din total 1270-60=1210
1210:11=110
1zi 110×5
2zi 110
3zi 550+60