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Sergiu99
a fost răspuns

Efectuati 2+[√1152-√48 x (√432-√192)] :24

Răspuns :

Iakabcristina2
1152=2•26^2 (^ înseamnă la putere) => rad1152=26rad2
48=2^4•3 => rad48=4rad3
432=2^4•3^3 => rad432=12rad3
192=2^6•3 => rad192=8rad3

2+(26rad2-4rad3•4rad3):24=
2+(26rad2-48):24=
2+(13rad2-24)/12=
(24+13rad2-24)/12=
13rad3/12
Dede13
√1152=24√2
√48=4√3
√432=12√3
√192=8√3

2+[√1152-√48 x (√432-√192)] :24=
=2+[24√2-4√3×(12√3-8√3)]
=2+(24√2-4√3×4√3):24
=2+(24√2-4×4×3):24
=2+(24√2-48):24
=2+24(√2-2):24
=2+√2-2
=√2

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