Răspuns :
1/(√5-2) + 1/(√5+2)=
(√5+2+√5-2)/(√5-2)(√5+2)=
2√5/(5-4)=2√5=√20
(√5+2+√5-2)/(√5-2)(√5+2)=
2√5/(5-4)=2√5=√20
a=1/√5-2+1/√5+2=(√5+2)/(5-4)+(√5-2)/5-4=√5+2+√5-2=2√5=√2²*5=√20
a=√20∈(√19,√21)
a=√20∈(√19,√21)