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Stefaniastefy22
a fost răspuns

aflati2 nr naturale stiind ca produsul lor este 100 iar suma lor este 29 1x+2x+3x+...+100x=50.500



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Răspuns :

Renatemambouko
a×b=100
a+b=29
a=29-b
(29-b)×b=100
b²-29b+100=
Δ=(-29)²-4×1×100=841-400=
b=(29+√441)/2=(29+21)/2=25
a=100:25=4
b=(29-√441)/2=(29-21)/2=4
a=100:4=25


1x+2x+3x+...+100x=50500
x(1+2+3+..+100)=50500
x×100×101/2=50500
x×50×101=50500
x×5050=50500
x=10






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