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Afla suma numerelor a si b stiind ca a+116:2=(1991:11-4):3 si b:11-4=(4+110:2)x3

Ajuror pls

Răspuns :

Ivuraluca111
a+116:2=(1991:11-4):3
a+116:2=(181-4):3
a+116:2=59
a+58=59
a=1



b:11-4=(4+110:2)×3
b:11-4=(4+55)×3
b:11-4=59×3
b:11-4=177
b:11-4=177
b:11=177+4
b:11=181
b=181×11
b=1991

Suma nr. a si b: 1+1991=1992