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a fost răspuns

a + 3b =14
2b + 3c = 19
E1 = 2a + 8b + 3c =
E2 = 2a + 16b + 15c =
E1 , E2 = ?
Ps : E1 , E2 = exemplu 1 , exemplu 2


Răspuns :

a+3b=14
2b+3c=19
E1=2a+8b+3c
pe E1 o scriem:  E1=a+a+3b+3b+2b+3c  (am descompus)
am obtinut  E1=(a+3b)+(a+3b)+(2b+3c)
inlocuim  E1=14+14+19
             E1=47

E2=2a+16b+15c
E2=a+a+3b+3b+2b+2b+2b+2b+2b+3c+3c+3c+3c+3c
E2=(a+3b)+(a+3b)+(2b+3c)+(2b+3c)+(2b+3c)+2b+3c)+(2b+3c)
E2=(2x14)+(5x19)
E2=28+95
E2=123

Didi12342
a + 3b = 14 |×2

2a + 6b = 28
2b + 3c = 19
adunam cele 2 relatii
2a + 6b + 2b + 3c =
= 2a + 8b + 3c = 28 + 19 = 47

2b + 3c = 19 |×5

10b + 15c = 95
2a + 6b = 28
adunam:
2a + 6b + 10b + 15c =
= 2a + 16b + 15c =
= 95 + 28 =
= 123

E1 = 47
E2 = 123