[tex]\it 7^{120} : 49^{60} +8^{30}:16^{22} +100^{20}:10^{38} -7\cdot3\cdot5 =
\\\;\\
=7^{120} :(7^2)^{60} +(2^3)^{30}:(2^4)^22+(10^2)^{20}:10^{38} -103 = [/tex]
[tex]\it = 7^{120}:7^{120} +2^{90}:2^{88} +10^{40}:10^{38} -105 =
\\\;\\
= 1+4+100-105 = 0
[/tex]
