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a fost răspuns

[tex]( \sqrt{300} - \sqrt{48} + \frac{1}{3} \sqrt {27} ) : \sqrt{3} [/tex]

Răspuns :

Angelicus
[tex]=( \sqrt{3*100}- \sqrt{3*16}+ \frac{1}{3 } \sqrt{3*9}): \sqrt{3}=(10 \sqrt{3}-4 \sqrt{3}+ \sqrt{3}): \sqrt{3}= [/tex]
[tex]=10 \sqrt{3}: \sqrt{3}-4 \sqrt{3}: \sqrt{3}+ \sqrt{3}: \sqrt{3}=10-4+1=7 [/tex]