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Afla suma numerelor a si b stiind ca a+116:2=(1991:11-4):3sib:11-4=(4+110:2)*3

Răspuns :

Didi12342
a+116:2=(1991:11-4):3
a + 58 = (181 - 4) : 3
a + 58 = 177 : 3
a + 58 = 59
a = 59 - 58
a = 1

b:11-4=(4+110:2)*3
b : 11 - 4 = (4+55)*3
b : 11 - 4 = 59 * 3
b : 11 = 177 + 4
b : 11 = 181
b = 181 × 11
b = 1 991

a + b = 1 + 1 991 = 1 992
RebelStar555
a+58=(181-4):3=59
a+58=59
a=1
b:11-4=(4+55)×3=177
b:11=177+4=181
181×11=1991
b=1991
1+1991=1992

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