Răspuns :
x/y=2/3=>x/2=y/3=k=>x=2k si y=3k
3x+2y/y-x=5k+6k/k=11k/k=11
3x+2y/y-x=5k+6k/k=11k/k=11
x/y=2/3=>x=2y/3
(3x+2y)(y-x)=(3*2y/3+2y)(y-2y/3)=(2y+2y)/(3y/3-2y/3)=4y/y/3=4y*3/y=12
sau
x/y=2/3=k=>x=2k și y=3k
(3x+2y)(y-x)=(3*2k+2*3k)/(3k-2k)=(6k+6k)/k=12k/k=12
(3x+2y)(y-x)=(3*2y/3+2y)(y-2y/3)=(2y+2y)/(3y/3-2y/3)=4y/y/3=4y*3/y=12
sau
x/y=2/3=k=>x=2k și y=3k
(3x+2y)(y-x)=(3*2k+2*3k)/(3k-2k)=(6k+6k)/k=12k/k=12