-calculez masa de NaOH care a fost dizolvat initial
c1=md1x100/ms1--->md1= c1xms1/100= 10x200/100= 20g
-masa celor 1,5mol se adauga atat la md cat si la ms
m=nxM---> M= 1,5molx40g/mol=60gNaOH
md2=20+60-> 80g
ms2=200+60-> 260g
c2= 80x100/260=.........................calculeaza !!!