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Vladatonofa31
a fost răspuns

Calculati:
a)√3(√27+4√3)
b)√2(2√2+√72)
c)(√3+2)²-√12
d)3√80+(6-√5)²-40
e)(√45-√5)²-20
f)√45-√75supra√3-√5

Răspuns :

Renatemambouko
a)√3(√27+4√3) =√3(3√3+4√3) =√3×7√3=3×7=21

b)√2(2√2+√72)=√2(2√2+6√2)=√2×8√2=8×2=16

c)(√3+2)²-√12=3+4√3+4-2√3=7+2√3

d)3√80+(6-√5)²-40=12√5+36-12√5+5-40=41-40=1

e)(√45-√5)²-20=(3√5-√5)²-20=(2√5)²-20=20-20=0

f)(√45-√758)/(√3-√5)

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