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Determinati multimile: Numerele naturale:[tex]A= \frac{15}{X+7} B= \frac{12}{2X+3} [/tex]

Răspuns :

Anelira
x+7∈D₁₅ ⇒x+7∈{1,3,5,15} /-7
x∈{-6,-4,-2,8} dar x∈ N ⇒x=8 ⇒A={8}
ptr multimea B ⇒ 2x+3∈D₁₂ ⇒ 2x+3∈{1,2,3,4,6,12} /-3 ⇒
2x∈{-2,-1,0,1,3,9} /÷2
x∈{-1,-1/2,0,1/2 ,3/2, 9/2} dar x∈N ⇒B={0}

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