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a fost răspuns

Descompuneti in factori :a) (3x+1)la puterea2 -(x+3)la puterea 2
b) (3x+5)la puterea 2-(x+1)la puterea 2
c) (x+radical din 2)-8

Răspuns :

Bruneta771
a) [(3x+1)-(x+3)[(3x+1)+(x+3)]=(3x+1-x-3)(3x+1+x+3)=(2x-2)(4x+4)=2(x-1)(2x-2)b); [(3x+5)-(x+1)][(3x+5)+(x+1)]=(3x+5-x+1)(3x+5+x+1)=(2x+6)(4x+6)=2(x+3)(2x+3); c) (x√2-8)la puterea2=(x√2-8)la put 2-2•x√2•8+8 la put 2=2xla put 2-16x√2+64

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