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Cryn1
a fost răspuns

va rog cine poate ajuta

daca a+b=11,b+c=14 si c+a=13, calculati .
.a+b+c,
2a+2b+2c,
3c+5b+2c
ab+ac+10c

multumesc

Răspuns :

Renatemambouko
a+b=11
b+c=14
c+a=13
a+b+b+c+c+a=11+14+13
2(a+b+c)=38
a+b+c=38:2=19
a=19-14=5
b=19-13=6
c=19-11=8
2a+2b+2c=2(a+b+c)=2*19=38 
3c+5b+2c=5c+5b=5(b+c)=5*14=70
ab+ac+10c=a(b+c)+10c=5*14+10*8=70+80=150