aliajul=Cu si Al=10g
Cu+HCl=nu reactioneaza
2Al+6HCl=2AlCl₃+3H₂
1mol....................22.4L
x moli...................8 L
x=8*1/22.4=0.357 moli Hidrogen
1mol.............................2g
0.357 moli....................y
y=0.357*2/1=0.714g Hidrogen
z=masa de aluminiu intrata in reactie
z=2*27*0.714/6=6.426 g Aluminiu
⇒Cuprul=3.574 g