b) 50500:(1+2+3+...+100) = 5050:[100(100+1)/2)=5050: (50*101)= 1
c) 111|(abc+bca+cab) = 1/(a+b+c)
abc+bca+cab=100a+10b+c+100b+10c+a+100c+10a+b=111a+111b+111c=
111(a+b+c)
d) 21|(1+2+3+...+20) = 21/[20(20+1)/2]=21/10*21=1/10
a)30^n / [ 5^n . 6^n + 15^n . 2^(n+1 )] =30^n / ( 5^n . 2^n . 3^n + 3^n . 5^n. 2^n .2 ) =
30^n / 30^n( 1+2 ) = 1/3