Ca(OH)2+ 2HCl=CaCl2+2H2O
1. Calculam masa de hidroxid de calciu dizolvata:
[tex]md= \dfrac{c*ms}{100}= \dfrac{10*200}{100}=20\ g \ Ca(OH)2[/tex]
2. Calculam masele moleculare pentru substantele care ne intereseaza:
[tex]M_{Ca(OH)2} =40+2*16+2*1=74[/tex]
[tex]M_{HCl}=1+35,5=36,5 [/tex]
[tex]M_{CaCl2}=40+2*35,5=40+71=111 [/tex]
3. Aflam masa dizolvata de HCl si masa de CaCl2 ce se obtine din reactie:
74 g Ca(OH)2........73 g HCl......111 g CaCl2
20 g Ca(OH)2.............x...................y
[tex]x= \dfrac{20*73}{74}=19,73 \ g\ HCl[/tex]
[tex]y= \dfrac{20*111}{74}=30 \ g \ CaCl2 [/tex]
a) [tex]ms_{HCl} = \dfrac{x*100}{c}= \dfrac{1973}{3,65} =540,55 \ g \ solutie[/tex]
b) [tex]n_{CaCl2}= \dfrac{30}{111}=0,27 \ moli[/tex]
Sper ca te-am ajutat si ca ai inteles :)
