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[(25*2)*10 : 125*13 +3]*15 : (4×2*20)*2 - 2*0
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Răspuns :

Didi12342
[(25^2)^10 : 125^13 +3]^15 : (4×2^20)^2 - 2^0 =
= (25^20 : 5^39+3)^15 : (2^22)^2- 1 =
= (5^40:5^39+3)^15 : 2^44 - 1 =
= (5^1+3)^15 : 2^44 - 1 =
= 8^15: 2^44 - 1 =
= 2^45 : 2^44 - 1 =
= 2^1 - 1 =
= 1

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