Răspuns :
3^2006=3² *3^2004=9*3^2004= (1+4+4) *(3^1002)²= (1²+2²+2²)*(3^1002)²=
(3^1002)²+ (2*3^1002)² + (2*3^1002)², suma de trei patrate perfecte
(3^1002)²+ (2*3^1002)² + (2*3^1002)², suma de trei patrate perfecte
3^2006=3^4 * 3^2002=(1+16+64)(3^1001)^2=
=(3^1001)^2 + (4*3^1001)^2 + (8*3^1001)^2
=(3^1001)^2 + (4*3^1001)^2 + (8*3^1001)^2