Răspuns :
notam AB=x
teorema unghiului de 30° ⇒BC=2AB=2x
teorema lui Pitagora AC=√[(2x)²-x²]=√3x²=x√3
teorema catetei
AB²=BD×BC=BD×2x x²=BD×2x BD=x/2
DC=BC-BD=2x-x/2=3x/2
BD/DC=(x/2)/(3x/2)
BD/DC=x/2 × 2/3x=1/3
DC=3BD
teorema unghiului de 30° ⇒BC=2AB=2x
teorema lui Pitagora AC=√[(2x)²-x²]=√3x²=x√3
teorema catetei
AB²=BD×BC=BD×2x x²=BD×2x BD=x/2
DC=BC-BD=2x-x/2=3x/2
BD/DC=(x/2)/(3x/2)
BD/DC=x/2 × 2/3x=1/3
DC=3BD