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a fost răspuns

Descompuneti in factori primi:
3x³+6x+3x=
x³+3x²-4x-12=
x³+2x²-9x-18=

Răspuns :

3x³+6x+3x= 3x(x²+2+1)= 3x(x²+3)

x³+3x²-4x-12= x²(x+3)-4(x+3)= (x+3)(x²-4)= (x+3)(x-2)(x+2)

x³+2x²-9x-18= x²(x+2)-9(x+2)= (x+2)(x²-9)= (x+2)(x-3)(x+3)

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