👤
a fost răspuns

Vaaa roggg ajutooorrrrrr
Sa se resolve in R ecuatia
|x+4|=x-3

Răspuns :

Rayzen
[tex]\big|x+4\big| = x-3\\ \\$Conditie de existenta:\quad $ x-3\geq0 \Rightarrow x\geq3 \Rightarrow D = [3,+\infty)\\ \\\sqrt{(x+4)^2} = x-3 \Big|^2 \\ \\ \Big(\sqrt{(x+4)^2}\Big)^2 = (x-3)^2 \\ \\ (x+4)^2 = (x-3)^2\\ \\ x^2+2\cdot x\cdot 4+4^2= x^2-2\cdot x\cdot 3+3^2 \\ \\ x^2+8x+16 = x^2-6x+9 \\ \\ x^2-x^2+8x+6x = 9-16 \\ \\ 14x = -7 \\ \\ x = \dfrac{14}{-7} \\ \\ x = -2 \notin D \\ \\ \Rightarrow \boxed{S = \emptyset}[/tex]

Alte intrebari