2C₂H₂+5O₂=4CO₂+2H₂O
Masa molara C₂H₂=2*12+2*1=26
Masa molara CO₂=1*12+16*2=44
x=masa de CO₂ obtinuta
x=5.2*4*44/2*26=17.6g CO₂
1mol........................44g
y moli.........................17.6
y=17.6/44=0.4 moli CO₂
1mol...................22.4L
0.4moli...................z
z=0.4*22.4=8.96L CO₂.
