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Calculati:a)(1intreg 1 pe5)la puterea2-(7pe10)la puterea2+(1intreg1pe5-7pe10)la puterea2 varog repede

Răspuns :

Renatemambouko
a)(1intreg 1/5)²-(7/10)²+(1intreg1/5-7/10)²=
=(6/5)²-(7/10)²+(6/5-7/10)²=
=(6/5-7/10)(6/5+7/10)+[(12-7)/10]²=
=(12-7)/10 × (12+7)/10+(5/10)²=
=5/10 × 19/10+(1/2)²=
=1/2 × 19/10+1/4=
=19/20+1/4=
=(19+5)/20=
=24/20=6/5