Folosesti relatia c%= mdx100/ms, de unde md= cxms/100
c-conc. procentuala, md- masa de subst.dizolvata, ms-masa de solutie
ms1=100g
c1=10%---> md1=10g
ms2=400g
c2= 8%---> md2=32g
ms3=ms1+ms2= 500g
md3=md1+md2= 42g----------------> c3= 42x100/500=................calculeaza !
trebuie sa-ti dea o valoare cuprinsa intre 10% si 8% !
aflu md 1: md1= c1xms1/100=5x95/100= >4,75g
in solutia 2: md2=md1+5= 9,75g
ms2= ms1+5=100g
calculeaza c2= md2x100/ms2=.........................................................!!!!!