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Determina numarul natural n , stiind ca : a) 4^n+3 =8^6 ; b) 4^n + 4^n+1 + 4^n+2 = 21

Răspuns :

Ralucamaria5995
4^n+3 =8^6
2^2(n+3)=2^(3*6)
2(n+3)=3*6
2n+6=18
2n=12
n=6

4^n + 4^n+1 + 4^n+2 = 21
4^n(1+4+16)=21 I:21
4^n=1
4^n=4^0
n=0


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